[Solution]Kinetics ̶ Rates Of Reaction

Kinetics ̶ Rates Of Reaction (Total 15 Marks) 1-Bromobutane was hydrolysed by aqueous sodium hydroxide solution. C4H9Br + NaOH → C4H9OH + NaBr 1-Bromobutane Butan-1-ol…

Kinetics ̶ Rates Of Reaction (Total 15 Marks) 1-Bromobutane was hydrolysed by aqueous sodium hydroxide solution. C4H9Br + NaOH → C4H9OH + NaBr 1-Bromobutane Butan-1-ol During the reaction the sodium hydroxide is used up. Samples of the reaction mixture were drawn off at regular time intervals and analysed by titration with standard hydrochloric acid to find out the concentration of NaOH. The results are given in the table below: Time / secs Concentration of OH- / mol dm-3 0 0.500 100 0.350 200 0.250 300 0.180 400 0.125 500 0.090 600 0.063 700 0.040 800 0.030 (a) From the above information, Plot a suitable graph. The graph MUST be a hand drawn (plotted) graph. (3 Marks) (b) Select 4 suitable points along your graph [see part (a)] and draw tangents to find the rates. Construct a table of “Rate” against “Concentration”. Note: The rates need to be calculated and the calculations shown. (4 Marks) (c) Plot a graph of Rate against Concentration. The graph MUST be a hand drawn (plotted) graph. (3 Marks) (d) From your graph in part (c) deduce the Order of Reaction. (1 Mark) (e) Write a rate equation with respect to concentration of hydroxide ions. (2 Marks) (f) Calculate the rate constant k from the gradient of the graph, drawn in part (c). Show and explain your working. (2 Marks) Please note: The hand drawn graphs must be scanned and included as part of the word-processed answer (document) and should be of a suitable size such as A4 – This is the version that will be marked. Hand in the hand drawn graphs (unaltered from the e-version) with your name and KU ID number in the chemistry workshops on week commencing Monday 17th February 2020, as a means to allow the markers clarification if required at the time of marking.
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